X²+y²=26, xy=3, then
(a) x+y=?
(b) x-y=?
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x^2+y^2=(x+y)^2-2*x*y
=(x-y)^2+2*x*y
Here we can find out the value of (x+y) and (x-y) using the above mentioned formula and finally we obtain,
x+y=4*sq. root of 2
x-y=2*sq. root of 5
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