Question

x²+y²=29 and xy=2. Find the value i) (x+y) ii) x-y iii) x⁴+y⁴​

Answer 1

Answer:

Given X2+Y2 = 29 and XY =2

We know that ( X2+Y2)2 = (X2)2 + (Y2)2 + 2* X2*Y2

or (29)2 = X4 +Y4 + 2*(XY)2

or 841 = X4 +Y4 + 2*(2)2

or X4 +Y4 = 841 - 8 = 833 (Ans

Answer 2

$Answer$ ☝☝