x2+y2=29xy find the value of x and y
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Hey,
In the equation take xy common in the lhs
xy(x+y)=29xy
x+y=29 (as xy is cancelled)
Therefore,
x=29-y
Now,substituting X's value in the equation x+y=29,
(29-y) +y=29
29-y=29-y
y=0 and x=29.
Hope this helps!!
In the equation take xy common in the lhs
xy(x+y)=29xy
x+y=29 (as xy is cancelled)
Therefore,
x=29-y
Now,substituting X's value in the equation x+y=29,
(29-y) +y=29
29-y=29-y
y=0 and x=29.
Hope this helps!!
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