Math, asked by rudythesmartone, 3 months ago

x²+y²+2xy-z²(factorization)​

Answers

Answered by Anonymous
1

Step-by-step explanation:

870 053 1109

123456

U KNOW WHERE U HAVE TO COME ONLY WHO CAN SHOW

Answered by Heroicheist
7

Answer:

ur answer is here

Step-by-step explanation:

Factorisation of x^2+y^2-z^2-2xyx

2

+y

2

−z

2

−2xy is (x-y+z)(x-y-z).

Step-by-step explanation:

We have to factorise,

x^2+y^2-z^2-2xyx

2

+y

2

−z

2

−2xy

= x^2+y^2-2xy-z^2\ [(a-b)^2 =a^2+b^2-2ab]

2

+y

2

−2xy−z

2

[(a−b)

2

=a

2

+b

2

−2ab]

= (x-y)^2-z^2\ [(a-b)(a+b)=a^2-b^2](x−y)

2

−z

2

[(a−b)(a+b)=a

2

−b

2

]

= (x-y+z)(x-y-z)

Hence,factorisation of x^2+y^2-z^2-2xyx

2

+y

2

−z

2

−2xy is (x-y+z)(x-y-z).

itna madat ki brainliest to dedo yer

Similar questions