Question

x²+y²-3 from 3x²-1/2 y²​

Answer 1

Solution

Verified by Toppr

First, adding 3x2+5xy+7y2+3 and 2x2−4xy−3y2+7, we have 

= 3x2+5xy+7y2+3+2x2−4xy−3y2+7 

= 5x2+xy+4y2+10 

Now, 

Subtracting 5x2+xy+4y2+10 from 9x2−8xy+11y2 

= (9x2−8xy+11y2)−(5x2+xy+4y2+10) 

= 9x2−8xy+11y2−5x2−xy−4y2−10 

= 4x2−9xy+7y2−10