Question

x²+y²=34xy then prove that 2log(x+y)=2log3+2log2+logy

Answer 1

Hi ,

It is given that ,

x² + y² = 34xy

Add 2xy both sides of the equation,

x² + y² + 2xy = 34xy + 2xy

( x + y )² = 36xy

( x + y )² = 6²xy

Take logarithm both sides ,

log ( x + y )² = log [ 6²xy ]

2log ( x + y ) = log 6²+log x + log y

[ Since 1 ) log a^n = n log a ,

2 ) log ab = log a + log b ]

2 log ( x + y ) = 2log 6 + log x + logy

2log(x + y) = 2log(2 × 3)+logx+logy

2log(x + y) = 2(log2 +log3)+logx+logy

2log(x+y)=2log2+2log3+logx+logy

Hence proved.

I hope this helps you.

: )

Answer 2

answer

• hence proved

please mark me as brain list