Question

x²-y²=6 (x+y)= √3. (x-y)²=?

Answer 1

Answer:

The answer is 12

Step-by-step explanation:

Given $x^2-y^2=6$ and $x+y=\sqrt 3$

We know that $x^2-y^2=(x+y)(x-y)$

                      $\Rightarrow 6=\sqrt3(x-y)$, substitute the given values

                     $\Rightarrow x-y=\frac{6}{\sqrt 3}\\\therefore (x-y)^2=\frac{6^2}{(\sqrt 3)^2}=\frac{36}{3}=12$