Question

x2 + y2 = 65 and xy = 28 find the value of x+y​

Answer 1

Answer:

11

Step-by-step explanation:

${(x + y)}^{2} = {x}^{2} + {y}^{2} + 2xy \\ {(x + y)}^{2} = 65 + 2 \times 28 \\ {(x + y)}^{2} = 65 + 56 \\ {(x + y)} ^{2} = 121 \\ x + y = \sqrt{121 } \\ x + y = 11$

Answer 2

(x+y)^2=x2+y2+2xy

"=65+2*28

"=65+56

"=121

(x+y)^2=121

x+y=√121=11