Question

x2-y2-6ax+2ay+8a2 factorise it

Answer 1

Answer:

Step-by-step explanation:

Our aim is to factorize $x^{2} -y^{2} - 6ax + 2ay + 8a^{2}$.

Lets apply some rules of distribution, hence we get:

$x^{2} - y^{2} - 2a(3x - y - 4a)\\ =(x-y)(x+y)-2a(3x+3y-4y+4a)\\ =(x-y)(x+y)-2a(3(x+y)-4(y+ a))\\ =(x-y)(x+y)-6a(x+y) + 8a(y+a)\\ =(x+y)[x-y-6a]+8a(y+a)$

We must use several distributive properties as well as some concepts of basic algebra, and then we only need to think about what is the best way to reach our final answer, so never forget to think about each step you take.

Hope this helped you!!

Answer 2

Answer:

(x+y-4a) (x-y-2a)

Step-by-step explanation:=x2-2*x*3a+(3a)2-y2

                                           =(x-3a)2-(y2-2ay+a2)

                                           =(x-3a)2-(y-a)2

                                           =(x-3a+y-a)(x-3a-y+a)

                                           =(x-4a+y)(x-2a-y)

                                           =(x+y-4a)(x-y-2a)