Math, asked by akash923265biswas, 9 months ago

(x2 - y2) (a2– b2) + 4abxy​

Answers

Answered by mysticd
17

( - )(-b²) + 4abxy

= ( - ) - ( - ) + 4abxy

= x² - x² - y² + y² + 4abxy

= (x² + y² + 2abxy) - ( x² + y² - 2abxy )

= [ (ax)²+ (by)² + 2ax × by] - [(bx)² + (ay)² - 2bx×ay]

= ( ax + by )² - ( bx - ay )²

= [ (ax+by)+(bx-ay)][ (ax+by) - (bx-ay)]

= ( ax + by +bx - ay )(ax + by - bx + ay )

= ( ax + bx + by - ay )( ax - bx + by + ay )

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