Math, asked by Sejalrarhee0000, 6 months ago

x²-y²=[x+y] [x-y]
[2t]²-[5y]²

Answers

Answered by devnath54
2

Answer:

[2t]^2-[5y]^2

=[2t+5y] [2t-5y]

Step-by-step explanation:

Answered by Sakchhamraj
2

ANSWER:

(2t²)‐(5y)²

(2t‐5y)(2t+5y)

[(4t²+10ty)(‐10ty‐25y²)]

+10ty and ‐10ty got cancelled

so..

the answer is

( 4t²‐25y²)(4t²+25y²)

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