Math, asked by Shivshankar99, 10 months ago

X2+y2÷x2-y2=17/8,find the values of x:y.​

Answers

Answered by kobietten20061995
7

Answer:

(x^2+y^2)/(x^2-y^2)=17/8

17*(x^2+y^2)=8*(x^2-y^2)

17x^2+17y^2=8x^2-8y^2

17x^2-8x^2=-8y^2-17y^2

9x^2=-25y^2

(3x)^2=(5y)^2

3x=5y

x:y=5/3

Answered by asmitamaskey99
5

Check here....

It will be helpful

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