Math, asked by aman925545, 9 months ago

(x² - y²) (x²+y²) +(y²-z²) (y²+z²) +(z²-x²)(z²+x²) =0

Answers

Answered by manasvis2005
1

Using identity (a+b)(a-b)=a^2-b^2

Thus, x^4-y^4+y^4-z^4+z^4-x^4=0

Answered by sapnagharami1706
9

Answer:

This the answer of your question.

Hope this will help.

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