Math, asked by sjain20424, 7 days ago

(x²-y²)(x²+y²)+(y²-z²)(y²+z2)+(z²-x²)(z²+x2)=0

Answers

Answered by JuSTSiMplETHinGS

1

Answer:

Step-by-step explanation:

Using identity (a+b)(a-b)=a^2-b^2

Thus, x^4-y^4+y^4-z^4+z^4-x^4=0

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