Question

x²+y²=xy=0 or if x²+y²-xy=0find dy/do
​

Answer 1

(x

2

+y

2

)

2

=xy

x

4

+2x

2

y

2

+y

4

−xy=0

Differentiating w.r.t x,

4x

3

+2[x

2

.2y(

dx

dy

)+y

2

(2x)]+4y

3

(

dx

dy

)−[

dx

xdy

+y(1)]=0

(

dx

dy

)[4x

2

y+4y

3

−x]+4x

3

+4xy

2

−y=0

(

dx

dy

)[4x

2

y+4y

3

−x]=y−4x

3

−4xy

2

(

dx

dy

)=

4x

2

y+4y

3

−x

y−4x

3

−4xy

2

Answered B