Math, asked by anuchoudhary2109, 10 days ago

x²/y²+y²/x²= 14. then find the value of x³/y³+y³/x³.​

Answers

Answered by pranavpriyanshu007
1

Answer:

let's find out the solution:

  1. (x/y+y/x)^2= (x/y)^2+(y/x)^2+2 =14+2=16
  2. (x/y+y/x)^3 = (x/y)^3+(y/x)3+3(x/y×y/x)(x/y+y/x) , after putting the values,
  3. then finally we get, (x/y)3+(y/x)3 = 64-12=52
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