Question

(x²+y²);(-y²+z²);(-2z²-x²);(2x²y²+2y²z²+2z²x²)


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Answer 1

Answer:

Step-by-step explanation:

Given that,

( x² + y² ) ; ( - y² + z² ) ; ( - 2z² - x² ) ; (2x²y² + 2y²z² + 2z²x² )

= x² + y² + ( - y² + z² ) + ( - 2z² - x² ) + 2x²y² + 2y²z² + 2z²x²

= x² + y² - y² + z²- 2z² - x² + 2x²y² + 2y²z² + 2z²x² ( ∵ + × - = - )

= ( x² - x² ) + ( y² - y² ) + ( z²- 2z² ) + 2x²y² + 2y²z²+ 2z²x²

= - z² + 2x²y² + 2y²z² + 2z²x²