( x2 y2 z )expand the following
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Proof: Let x + y = k then, (x + y + z)2 = (k + z)2 = k2 + 2kz + z2 (Using identity I) = (x + y)2 + 2( x + y)z + z2 = x2 + 2xy + y2 + 2 xz + 2yz + z2 = x2 + y2 + z2 + 2xy + 2yz + 2zx ...
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