Math, asked by dikshagulati5142, 3 months ago

(x²+y²-z²)² -(x²-y²+z²)²​

Answers

Answered by labdhee82
0

(x²+y²-z²)² -(x²-y²+z²)²

x²+y²-z²+² - x²-y²+z²+²

x²+y²-z^4- x²-y²+z^4

Value of x

x² - x²

= 0 (0 cannot have power)

Value of y

y² - y²

= 0

Value of z

- z^4 + z^4

= 0

So,

0 + 0 - 0

= 0

So,

(x²+y²-z²)² -(x²-y²+z²)²

= 0

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