Question

=x2+y2+z2+2xy+2yz+2xz=? fast please no spam

Answer 1

= (x−y−z) 2

= (x−y−z) 2 since [(a−b−c)

= (x−y−z) 2 since [(a−b−c) 2 =a 2 +b 2 +c 2 −2ab+2bc−2ac]

= (x−y−z) 2 since [(a−b−c) 2 =a 2 +b 2 +c 2 −2ab+2bc−2ac]=∣x−y−z∣ [mod is applied since x−y−z may be negative]

Answer 2

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