Question

x²+y²+z²+2xy+2yz+2zx


if x=3
y=1
Z=-4

solve this also
x³+y³+z³-3xyz​

Answer 1

Answer:

$if \: x = 3 \\ y = 1 \\ z = 4 \\ so \: the \: equation \: is \\ {3}^{2} + {1}^{2} + {( - 4)}^{2} +( 2 \times 3 \times 1) + (2 \times 1 \times - 4) \\ = 9 + 1 + 8 + 6 - 8 \\ = 16$

Answer 2

Step-by-step explanation:

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