Question

x²+y²-z²-2xy factorise​

Answer 1

Step-by-step explanation:

Solution

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Given : x

2

+y

2

−z

2

−2xy

We can write it as

x

2

+y

2

−z

2

−2xy =(x

2

+y

2

−2xy)−z

2

So we get

x

2

+y

2

−z

2

−2xy =(x−y)

2

−z

2

Based on the equation a

2

−b

2

=(a+b)(a−b)

We get ,

x

2

+y

2

−z

2

−2xy =(x−y+z)(x−y−z)

Answer 2

Answer:

x²+y²-z²-2xy

= x²+y²-2xy-z² [(a-b)² =a²+b²-2ab]

= (x-y)²-z² [(a-b)(a+b)=a²−b²]

= (x-y+z)(x-y-z)