Question

(x²-yx²)dy+(y²-xy²)dx=0​

Answer 1

\left[x _{1}\right] = \left[ \frac{\frac{dx\,y^{2}}{2}+\frac{ - \sqrt{\left( \left( -4\right) \,dx\,dy\,y^{2}+4\,dx\,dy\,y^{3}+dx^{2}\,y^{4}\right) }}{2}}{dy-dy\,y}\right][x​1​​]=​⎣​⎡​​​dy−dyy​​​2​​dxy​2​​​​+​2​​−√​((−4)dxdyy​2​​+4dxdyy​3​​+dx​2​​y​4​​)​​​​​​​​⎦​⎤​​ Algebra equation functional value