Question

X2002 +10X2001 ÷ 10X2000 = 957.9

Answer 1

Answer:

x = -103 x = 93

Step-by-step explanation:

${x}^{2002} + {10x}^{2001} \div 10 {?}^{2000} = 957.9 \\ \frac{ {x}^{2002} + 10 {x}^{2001} }{10 {x}^{2000} } = 957.9 \\ \frac{ {x}^{2000} ( {x}^{2} + 10x) }{ {x}^{2000} \times 10 } = 957.9 \\ \frac{ {x}^{2} + 10x}{10} = 957.9 \\ {x}^{2} + 10x = 957.9 \times 10 \\ {x}^{2} + 10x = 9579 \\ {x}^{2} + 10x - 9579 = 0 \\ {x}^{2} + 103x - 93x - 9579 = 0 \\ x(x + 103) - 93(x + 103) = 0 \\ (x + 103)(x - 93) = 0 \\ x + 103 = 0 \: \: \: \: \: x - 93 = 0 \\ x = - 103 \: \: \: \: \: \: \: \: \: x = 93$

hope you get your answer

Answer 2

x = 93  or, x = - 103

Step-by-step explanation:

We have,

$\dfrac{x^{2002}+10x^{2001}}{10x^{2000}} =957.9$

To find, the value of x = ?

∴ $\dfrac{x^{2002}+10x^{2001}}{10x^{2000}} =957.9$

⇒ $\dfrac{x^{2002}}{10x^{2000}}+\dfrac{10x^{2001}}{10x^{2000}} =957.9$

⇒ $\dfrac{x^{2002-2000}}{10}+x^{2001-2000}=957.9$

⇒ $\dfrac{x^{2}}{10}+x=957.9$

⇒ $\dfrac{x^{2}+10x}{10}=957.9$

By crossmultiplication, we get

⇒ $x^{2}+10x=957.9\times 10=9579$

⇒ $x^{2}$ + 10x - 9579 = 0

⇒ $x^{2}$ + 103x - 93x - 9579 = 0

⇒ x(x + 103) - 93(x + 103) = 0

⇒ (x - 93)(x + 103) = 0

⇒ x - 93 = 0 or, x + 103 = 0

⇒ x = 93  or, x = - 103

∴ x = 93  or, x = - 103