Question

X²8how to find roots of quadratic equation class 10 of x²-8x+2

Answer 1

Answer:

The roots are 0.26 and 7.74

Step-by-step explanation:

x²-8x+2

Use the quadratic formula = $\frac{-b+ \sqrt{b^2 - 4ac} }{2a}$ or $\frac{-b- \sqrt{b^2 - 4ac} }{2a}$

a = 1 , b = -8 and c = +2

First we put the values in the positive equation  $\frac{-b+ \sqrt{b^2 - 4ac} }{2a}$

=$\frac{-(-8)+ \sqrt{(-8)^2 - 4X1X2} }{2X1}$

=$\frac{8+ \sqrt{64 - 8} }{2}$ =$\frac{8+ \sqrt{56} }{2}$=  $\frac{8+ 2\sqrt{14} }{2}$ = $\frac{8+ 7.48 }{2}$ = $\frac{15.48}{2}$ = 7.74

Now we substitute values in the negative equation $\frac{-b- \sqrt{b^2 - 4ac} }{2a}$

= $\frac{-(-8)- \sqrt{(-8)^2 + 4X1X2} }{2X1}$ = $\frac{8- \sqrt{56} }{2}$ =  $\frac{8- 2\sqrt{14} }{2}$ = $\frac{8- 7.48 }{2}$ = $\frac{0.52}{2}$ = 0.26