.x2d²y
- 8x
dy
+ 8y = log x
dx?
dx
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x3y′′′ = D(D – 1) (D – 2)y where D = d/dt Hence, the given d.e. becomes Read more on Sarthaks.com - https://www.sarthaks.com/365842/solve-x-3d-3y-dx-3-3x-2d-2y-dx-2-xdy-dx-8y-65cos-logx?show=365847#a365847
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