Math, asked by ansarif8278, 10 days ago

X²p²+xyp-6y²=0 where p=dy/dx

Answers

Answered by urmilabendale708
0

Step-by-step explanation:

Simplifying

x2p2 + xyp + -6y2 = 0

Reorder the terms:

pxy + p2x2 + -6y2 = 0

Solving

pxy + p2x2 + -6y2 = 0

Solving for variable 'p'.

Factor a trinomial.

(px + -2y)(px + 3y) = 0

Subproblem 1

Set the factor '(px + -2y)' equal to zero and attempt to solve:

Simplifying

px + -2y = 0

Solving

px + -2y = 0

Move all terms containing p to the left, all other terms to the right.

Add '2y' to each side of the equation.

px + -2y + 2y = 0 + 2y

Combine like terms: -2y + 2y = 0

px + 0 = 0 + 2y

px = 0 + 2y

Remove the zero:

px = 2y

Divide each side by 'x'.

p = 2x-1y

Simplifying

p = 2x-1y

Subproblem 2

Set the factor '(px + 3y)' equal to zero and attempt to solve:

Simplifying

px + 3y = 0

Solving

px + 3y = 0

Move all terms containing p to the left, all other terms to the right.

Add '-3y' to each side of the equation.

px + 3y + -3y = 0 + -3y

Combine like terms: 3y + -3y = 0

px + 0 = 0 + -3y

px = 0 + -3y

Remove the zero:

px = -3y

Divide each side by 'x'.

p = -3x-1y

Simplifying

p = -3x-1y

Solution

p = {2x-1y, -3x-1y

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