Question

x²sec²x + 2x .tanx then dy/dx

Answer 1

Step-by-step explanation:

we know , when a , function is product of two functions f(x) and g(x)

y = f(x).g(x)

then, dy/dx = g(x).df(x)/dx + f(x).dg(x)/dx

use this concept here,

y = x²tanx

dy/dx = x².d(tanx)/dx + tanx.d(x²)/dx

= x²sec²x + 2x .tanx

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