Question

x²t e
ау
x te
2
y +
log (aty)​

Answer 1

=log(x2ex)

⟹ey=x2ex

⟹ey.ex=x2

⟹ex+y=x2

⟹x+y=ln(x2)=2ln(x)

⟹y=2ln(x)−x

⟹dydx=2x−1

⟹d2ydx2=−2x2