Math, asked by abhi18789, 1 year ago

x2y = (2x+3y)3
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Answered by ajay8949

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Answer:

x²y = (2x + 3y)³

x²y = (2x)³ + (3y)³ + 3 × 2x × 3y (2x + 3y)

x²y = 8x³ + 27y³+ 18xy(2x + 3y)

x²y = 8x³ + 27y³ + 36x²y + 54 xy²

x²y - 36x²y = 8x³ + 27y³ +54 xy²

-35 x²y = 8x³ + 27y³ +54 xy²

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