Question

(X²y²-2)(1-2x²y²)


Find the product and verify the result (x=-1, y=2)


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Answer 1

answer is -14

Step-by-step explanation:

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Answer 2

$(x {}^{2} y {}^{2} - 2)(1 - 2 {x}^{2} {y}^{2} )$

$( {x}^{2} {y}^{2} - 2 {x}^{4} {y}^{4} - 2 + 4 {x}^{2} {y}^{2} )$

$(5 {x}^{2} {y}^{2} - 2 {x}^{4} {y}^{4} - 2)$

given

$x = - 1 \: \: \: \: \: \: y = 2$

substitute the value of x and y we have

$(5 \times ( - 1) {}^{2} \times {2}^{2} - 2 \times ( { - 1}^{4} ) \times {2}^{4} ) - 2)$

$(5 \times 1 \times 4 - 2 \times 1 \times 16 - 2)$

$(20 - 32 - 2)$

$(20 - 34)$

$- 14$

verify given

$( {x}^{2} {y}^{2} - 2)(1 - 2 {x}^{2 } {y}^{2} )$

$x \ = - 1 \: \: \: : \: y = 2$

$( { - 1}^{2} \times {2}^{2} - 2)(1 - 2 \times { - 1}^{2} \times {2}^{2} )$

$( 4 - 2)(1 - 8)$

$(2)( - 7)$

$- 14$proof huwa