(x²y²)² + 4x²y² solve
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x⁴y⁴+4x²y²
this is the answer because the powers are not same
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Answer:
(x²+y²)²
Here is your solution:
= (x²-y²)² + 4x²y²
= (x²)² – 2 × x² × y² + (y²)² + 4x²y²
= x⁴ –2x²y² + y⁴ + 4x²y²
= x⁴ + y⁴ + (-2x²y² + 4x²y²)
= x⁴ + y⁴ + 2x²y²
= (x² + y²)²
= (x² + y²) (x² + y²)
Hope it's helpful .
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