Question

x²y²-8xy-48 factorise​
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Answer 1

Answer:

Your answer

Step-by-step explanation:

By using middle splitting term let's factories:-

$$\{(xy)}^{2} - 8xy - 48 = 0$$

$$\implies$$ $$\ {x}^{2} {y}^{2} + 4xy - 12xy - 48= 0$$

Taking common,

$$\implies$$ $$\xy(xy + 4) - 12(xy + 4) = 0$$

$$\implies$$ (xy + 4)(xy - 12) = 0

$$\implies$$ xy + 4 = 0 either xy - 12 = 0

$$\implies$$ xy = -4 either xy = 12

Answer 2

Answer:

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