Math, asked by 9903825762, 20 days ago

(x²y²-x²), (xy²-2xy+x)

let's find the lcm in algebraic expressions​

Answers

Answered by deshrajguleria11
0

Factors of (x2y2-x2)

= x2 (y2-1)

= x2(y-1)(y + 1)

Factors of (xy2-2xy + x)

=x(y2-2y + 1)

=x(y-1) (y-1)

LCM is the lowest common multiple, which is the product of all the common factors taken once and the remaining factors as it is.

∴ the LCM of (x2y2-x2);(xy2-2xy + x) is x2(y-1)2(y + 1)

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