Math, asked by MdQamarImam, 1 year ago

x³+1/x³-2 Factorise the following

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Answered by kartikeya
31
12-Jul-2016 · x^3+(1/x)3 +1 - 3. =(x+1/x)^3 -3x.1/x(x+1/x) +( 1)^3–3. =(x+1/x)^3+(1)^3 - 3(x+1/x)-3. =(x+1/x +1){(x+1/x)^2 -(x+1/x)+1} -3(x+1/x+1).
Answered by annie115
27

Answer: a^3+b^3+c^3 -3.a.b.c=(a+b+c)(a^2+b^2+c^2-a.b-bc-ca)………….(1)

x^3 + 1/x^3 - 2

=x^3+1/x^3+1 -3

=(x)^3+(1/x)^3 +(1)^3–3.x.1/x.1

=(x+1/x+1)(x^2+1/x^2+1^2-x.1/x-1/x.1–1.x)

=(x+1/x+1)(x^2+1/x^2+1–1–1/x-x)

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