Question

(x3-19x-30)÷(x2-3x-10)​

Answer 1

Given funtion=x^3-19x-30 / x+3

x+3)x^3-19x-30(x^2-3x-10

(-)x^3+3x^2

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-3x^2-19x-30

(+)-3x^2-9x

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-10x-30

10x+30

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0

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x^3-19x-30 / x+3 = x^2-3x-10

x^2-3x-10=x^2+2x-5x-10

=x(x+2)-5(x+2)

=(x+2) (x-5)

x^3-19x-30 / (x+3) = (x+2) (x-5)