Math, asked by bnsravan22, 6 months ago

x³-23x²+142x-120 in maths please send answer​

Answers

Answered by anindyaadhikari13
6

I think, your question is about factorising the polynomial. Follow these,

 \sf {x}^{3}  - 23 {x}^{2}  + 142x - 120

 \sf =  {x}^{3}  -  {x}^{2}  - 22 {x}^{2}  + 22x + 120x - 120

 \sf =  {x}^{2} (x - 1) - 22(x - 1) + 120(x - 1)

 \sf = (x - 1)( {x}^{2}  - 22x + 120)

 \sf = (x - 1)( {x}^{2}  - 10x - 12x + 120)

 \sf = (x - 1)(x(x  - 10) - 12(x  - 10))

 \sf = (x - 1)(x - 10)(x - 12)

Hence, the factorised form is (x-1)(x-10)(x-12).

Answered by nehashanbhag0729
20

Answer:

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ur answer is in above attachment pic .

watch it out

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