Question

x³-27 factorization​

Answer 1

Answer:

x³-9x

Step-by-step explanation:

x³-3³

a³-b³ = (a-b)(a²+ab+b²)

x³-3³ = (x-3)(x²+x×3+3²)

x³-3³ = x-3(x²+3x+27)

x³-3³ = x(x²+3x+27)-3(x²+3x+27)

x³-3³ = x³+3x²+27-3x²-9x-27

x³-3³ = x³-9x+27-27-3x²+3x²

x³-3³ = x³-9x

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