Question

x3-2x^2y+3xy^2-6y^3​

Answer 1

Answer:

= x^2(x-2y) +3y^2(x-2y)

= (x-2y) (x^2+3y^2)

Answer 2

x³-2x²y+3xy²-6y³

x²(x-2y)+3y²(x-2y)

(x²+3y²)(x-2y)

x²+3y²=0

x²=-3y²

x=√-3y²

x-2y=0

x=2y

here your answer