x³-2x²-7x+12
what will be their zeros
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HERE IS UR ANSWER DEAR,
let x=1
p(1)= (1)³-2(1)²-7(1)+12
= 1-2-7+12
= 13-9
= 4
which is not equal to zero
let x= -1
p(-1)= (-1)³-2(-1)²-7(-1)+12
= -1 -2+7+12
= 19 -3
= 16
which is not equal to 0
let x= 2
p(2)= (2)³-2(2)²-7(2)+12
= 8-8 -14 +12
= -2
which is not equal to 0
let x= -2
p(-2)= (-2)³-2(-2)²-7(-2)+12
= -8 -8 +14+12
= -16 +16
= 0
therefore ,
-2 is the zero of the polynomial
x+2 is the factor of this p(x)
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