Math, asked by khtkkomal, 5 months ago

x³+3+²3x+1÷x+1
$(2x + 5y + 3z) {}^{2}$

Answers

Answered by DARYLL11234

6

Answer:

x³+3+²3x+1÷x+1

$(2x + 5y + 3z) {}^{2}$ x³+3+²3x+1÷x+1

$(2x + 5y + 3z) {}^{2}$

Step-by-step explanation:

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