Question

x3 +3x/3x2 +1=341/91

Answer 1

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Answer 2

Given,

         $\frac{x^3+3x}{3x^2+1} = \frac{341}{91}$

To find,

         Value of x

Solution,

    ⇒  $\frac{x^3+3x}{3x^2+1}=\frac{341}{91}$

We can solve this mathematical problem by using the following mathematical process.

The method of solving this equation is as follows.

Applying Componendo and Dividendo on both sides of the equation;

    ⇒  $\frac{x^3+3x+3x^2+1}{x^3+3x-3x^2-1} = \frac{341+91}{341-91}$   ( a:b::c:d,  $\frac{a+b}{a-b} =\frac{c+d}{c-d}$ )

    ⇒  $\frac{(x+1)^3}{(x-1)^3} = \frac{432}{250}$

Taking cube root on both sides of the equation;

    ⇒ $\frac{x+1}{x-1} = \frac{6\sqrt[3]{2} }{5\sqrt[3]{2} }$

    ⇒ $\frac{x+1}{x-1} = \frac{6}{5}$

    ⇒ 5x+5 = 6x-6

    ⇒ x = 11

As a result, the value of x in the given equation will be 11.