Question

(x3 + 3x – 6) + (-2x2 + x – 2) – (3x – 4)
simplify

Answer 1

$\huge{Solution}$

$( {x}^{3} + 3x - 6) + ( - {2x}^{2} + x - 2) - (3x - 4)$

Firstly, take the no.s out from the bracket.

Note:- Their signs will also be changed.

${x}^{3} + 3x - 6 - {2x}^{2} + x - 2 - 3x + 4$

Now add the common terms if there are.

+ 3x and -3x will be removed. Reason-- They are having different signs and when signs are different no..s are removed.

${x}^{3} - 6 - {2x}^{2} + x - 2 + 4$

${x}^{3} - {2x}^{2} + x - 4$

( Answer)

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Additional Information

➣ Signs are changed on the following bases.

(+) (+) = +

(-) (-) = +

(-) (+) = -

(+) (-) = -

Answer 2

Question :-

➣ Simplify :-

• $\sf\red{(x^3 + 3x - 6) + (-2x^2 + x - 2) - (3x - 4)}$

Solution :-

• Firstly, remove the brackets.

$\bold{Note~:-~While~removing~the~brackets~signs~will~be~changed}$

• $\sf{x^3 + 3x - 6 - 2x^2 + x - 2 - 3x + 4}$

• Add the like terms.

• $\sf{x^3 - 2x^2 + x - 4}$

+ 3x and - 3x will get cancelled because their signs are different.

Now arrange the terms according to the increasing order of their power.

$\sf\blue{Answer}$ $\implies$ $\bold{x - 4 - 2x^2 + x^3}$

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Signs are changed on the following bases :-

• (+) (+) = (+)
• (-) (-) = (+)
• (-) (+) = (-)
• (+) (-) = (-)