Question

x³+3x²+3x+1,2x+1 by long division method find the remainder​

Answer 1

Answer:

Dividend = x³+3x²+3x+1

Dividend = x³+3x²+3x+1Divisor = x - 1/2

Dividend = x³+3x²+3x+1Divisor = x - 1/2Quotient = x² + 7x/2 + 19/4Dividend = x³+3x²+3x+1Divisor = x - 1/2Quotient = x² + 7x/2 + 19/4Remainder = 27/8

Step-by-step explanation:

Given(x3+3x2+3x+1)÷(x−21)

Quotient :x²+7x/2+19/4

x-1/2)x³+3x²+3x+1(

***** x³ -x²/2

____________________

******** 7x²/2 +3x

7x²/2 -7x/4

_________________________

19x/4 +119x/4 -19/8Remainder (27/8)

Therefore,

Dividend = x³+3x²+3x+1

Divisor = x - 1/2

Quotient = x² + 7x/2 + 19/4

Remainder = 27/8