Question

x3+3x2+3x+1 factor Theorem x +1 ​

Answer 1

Answer:

$x + 1 = 0$

$x = - 1$

$By \: factor \: theorem,$

$p(x) = {x}^{3} + 3 {x}^{2} + 3x + 1$

$p( -1) = {( - 1)}^{3} + 3 {( -1 )}^{2} + 3( - 1) + 1$

$= - 1 + 3 - 3 + 1$

$= 0$

$Here \: the \: remainder \: is \: 0. So, \: x + 1 \: \: is \: a \: factor \: of \: {x}^{3} + 3 {x}^{2} + 3x + 1.$

Answer 2

Answer:

$hope \: its \: useful..........$