x3 + 3x2 - 4 by x-1 :-Divide
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Answer:
x-1 ) x3 + 3x2 + 0x - 4 ( x2 + 4x + 4
x3 - x2
- +
--------------------------------
0 + 4x2 + 0x
+ 4x2 - 4x
- +
----------------------------------
0 + 4x - 4
+ 4x - 4
- +
--------------------------------------
0
Therefore ,
(x^3-3x^2-4) ÷ (x+2) = (x^2 + 4x +4)
= x^2 +2x + 2x + 4
= x(x+2) + 2(x+2)
= (x+2)(x+2)
= (x+2)^2
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