Question

x³+3x²+5x+2 can have____
no of zeroes
(a) 1
(b) 2
(c) 3
(d) all of them.​

Answer 1

The discriminant of the above cubic equation is

(–59)

So, there is only one real root existing and rest two are imaginary

. So the option (a) is correct

The three roots are approximately:

x₁≈ −0.54660

x₂≈ −1.2267 + 1.4677i

x₃≈ −1.2267 − 1.4677i

where, i=√(−1)