Question

X3-3x2-x+3 if its one zero is 1 then find other

Answer 1

Dear friend your answer =
x = 1

x-1=0


X³-3x²-x+3
x-1)x³-3x²-x+3(x²-2x-3
x³-x²
(-) (+)
________
-2x²-x+3
-2x²+2x
(+) (-)
_____________
-3x +3
-3x +3
(+) (-)
_________
0

Now equ. = x²-2x-3
x² -3x+x-3
x(x-3) 1(x-3)
(x-3) (x+1)
x-3= 0
x=3
x+1 =0
x =-1
Zeros = -1,3,1.
it will help completely.
u will understand.

Answer 2

Answer:

We know that if x = a is a zero of a polynomial then x - a is a factor of f(x) Since - √2 and √2 are zeros of f(x) Therefore (x + √2) and (x - √2) are factors of f(x) Now on dividing f(x) = x3 + 3x2 - 2x - 6 by g(x) = (x - √2)(x + √2) = x2 - 2 to find other zeros. By applying division algorithm, we have: Hence, the zeros of the given polynomial are: -√2, √2, -3Read more on Sarthaks.com - https://www.sarthaks.com/1074839/find-all-the-zeros-of-the-polynomial-x-3-3x-2-2x-6-if-two-of-its-zeros-are-2-and-2