Question

x³-4x²+5x-2;2,1,1 please ans
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Answer 1

The possible zeros for the given are ±2, ±1. (Rational Zeros Theorem)

Let's put in x=1 and see it works.

The equation is true, therefore 1 is a zero.

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Since x=1 is a solution, it has x-1 as a factor. (Remainder Theorem)

Divide by the factor.

x³-4x²+5x-2=(x-1)(x²-3x+2)

So, x³-4x²+5x-2=(x-1)(x-1)(x-2)

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Therefore, its three zeros are 1, 1, 2.