Question

(x3+4x2-8) by (x+3)​

Answer 1

Answer:

I think your question is

${x}^{3} + 4 {x}^{2} - 8 \div x + 3$

x+3)x^3+4x^2+0x-8(x^2+x+3

$\underline{x^3+3x^2}$

x^2+0x

$\underline{x^2+3x}$

3x-8

$\underline{3x+9}$

$\boxed{1}$

remainder is 1

it is division buddy

I hope it helps you